How do you convert #(6,9)# to polar form?
1 Answer
May 18, 2016
Explanation:
Using the formulae that links Cartesian and Polar coordinates.
#•r=sqrt(x^2+y^2)#
#•theta=tan^-1(y/x)# here x = 6 and y = 9 : Substitute these values into the formulae.
#rArrr=sqrt(6^2+9^2)=sqrt117" in simplest form"# and
#theta=tan^-1(9/6)=0.983" radians"#
#rArr(r,theta)=(sqrt117,0.983)=(sqrt117,56.3^@)#
