How do you convert # (4, 3pi/2)# to rectangular form? Trigonometry The Polar System Converting Between Systems 1 Answer Shwetank Mauria Mar 10, 2016 #(4,(3pi)/2)# in polar coordinates is #(0,-4)# in rectangular coordinates. Explanation: #(r,theta)# in polar coordinates is #(rcostheta,rsintheta)# in rectangular coordinates. Hence, #(4,(3pi)/2)# in polar coordinates in rectangular coordinates is #(4cos((3pi)/2),4sin((3pi)/2))# or #(4xx0,4xx(-1))# or #(0,-4)# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 5565 views around the world You can reuse this answer Creative Commons License