How do you convert #(3sqrt(2), 3sqrt(2))# into polar form?

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Answer 1 · 2016-08-28T23:57:01

#{3 sqrt(2), pi/4}#

The point #(3sqrt(2), 3sqrt(2))# in polar coordinates

#r cos theta = 3sqrt(2)#
#r sin theta = 3sqrt(2)#

dividing term to term

#tan theta = 1#

squaring and adding

#r^2=(3 sqrt 2)^2#

Finally in polar coordinates

#{3 sqrt(2), pi/4}#