How do you convert #θ = (3 pi )/ 4# into cartesian form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer Tony B Jul 1, 2016 #theta =(3pi)/4 -> P_1->(x,y)=(rcos((3pi)/4),rsin((3pi)/4))# Explanation: Let #(0,0)" to point "(x,y)" be "r# Then we have #x=rcos(theta)" ; "y=rsin(theta)# So #theta =(3pi)/4 -> P_1->(x,y)=(rcos((3pi)/4),rsin((3pi)/4))# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 3631 views around the world You can reuse this answer Creative Commons License