How do you convert #2=(8x-y)^2-5y+7x# into polar form? Trigonometry The Polar System Converting Between Systems 1 Answer Yonas Yohannes Jan 18, 2016 #(64x^2- 16xy+y^2)-5y+7x-2=0# Now sub: #x= rcostheta; y=rsin theta# Noting that #r=x^2+y^2; theta=tan^-1 (y/x)# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1237 views around the world You can reuse this answer Creative Commons License