How do you convert # (-2, 2sqrt3)# to polar form? Trigonometry The Polar System Converting Between Systems 1 Answer Binayaka C. May 22, 2016 In Polar form #(r,theta)# is #4,120^0# Explanation: Polar distance #r=sqrt((-2)^2+(2sqrt3)^2)=4# #theta=tan^-1((2sqrt3)/-2)=tan^-1(- sqrt3) =120^0# since the point is on 2nd quadrant [Ans] Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1185 views around the world You can reuse this answer Creative Commons License