How do you convert #(-2, -2sqrt3)# to polar form? Trigonometry The Polar System Converting Between Systems 1 Answer A. S. Adikesavan Mar 1, 2016 ( 4, 4#pi#/3 ) Explanation: ( x, y ) = ( #-#2, #-#2#sqrt#3 ) r = #sqrt#(x^x + y^y). cos #theta# = x/r and sin #theta# = y/r. cos (#pi# + #theta#) = #-# cos #theta#. sin (#pi# + #theta#) = #-# sin #theta# Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 1203 views around the world You can reuse this answer Creative Commons License