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How do you convert # (-2, 2)# to polar form?

1 Answer

Shwetank Mauria

May 2, 2016

#(-2,2)# in polar form is #(2sqrt2,(3pi)/4)#

Explanation:

#(a,b)# in polar form is #(r,theta)# where #r=sqrt(a^2+b^2)# and #tantheta=b/a#

Hence #(-2,2)# in polar form is #(r,theta)# where

#r=sqrt((-2)^2+2^2)=sqrt(4+4)=sqrt8=2sqrt2# and

#tantheta=2/(-2)=-1=(3pi)/4#

Hence #(-2,2)# in polar form is #(2sqrt2,(3pi)/4)#

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