How do you convert #(1, sqrt3)# into polar form?
2 Answers
Mar 12, 2018
See below
Explanation:
The pole
Mar 12, 2018
Explanation:
#"to convert from "color(blue)"cartesian to polar form"#
#"that is " (x,y)to(r,theta)" using"#
#•color(white)(x)r=sqrt(x^2+y^2)#
#•color(white)(x)theta=tan^-1(y/x)#
#"here "x=1" and "y=sqrt3#
#rArrr=sqrt(1^2+(sqrt3)^2)=2#
#rArrtheta=tan^-1(sqrt3)=pi/3#
#rArr(1,sqrt3)to(2,pi/3)#