How do you convert # (−1, 5)# into polar form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer sankarankalyanam Jul 9, 2018 #color(purple)((r, theta) = (sqrt26, 101.31^@)# Explanation: #"Conversion from rectangular to polar coordinates "# #r = sqrt (x^2 + y^2), theta = arctan (y/x)# #(x,y) = 9-1,5)# #r = |sqrt(-1^2 + 5^2)| = sqrt26# #theta = arctan (5/-1) ~~ 101.31^@, " as in II Quadrant"# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 3424 views around the world You can reuse this answer Creative Commons License