How do you convert $(0, 6)$ $(0, 6)$ to polar form?

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How do you convert $(0, 6)$ $(0, 6)$ to polar form?

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Answer 1 · 2017-11-20T19:40:58

See explanation.

Explanation:

graph{(x^2+(y-6)^2-0.1)=0 [-20.27, 20.26, -10.14, 10.13]}

The point $(0, 6)$ $(0,6)$ lies on the positive (upper) part of $Y$ $Y$ axis, so the angle between the positive part of the $X$ $X$ axis and the line containing the point is $\frac{π}{2}$ $pi/2$ , the distance between the point $(0, 6)$ $(0,6)$ and the origin is $r = 6$ $r=6$ , so the polar coordinates of $(0, 6)$ $(0,6)$ are:

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How do you convert $(0, 6)$ $(0, 6)$ to polar form?

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Explanation:

${(r=6),(varphi=pi/2):}$

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How do you convert (0, 6)(0,6)(0, 6) to polar form?

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Explanation:

{(r=6),(varphi=pi/2):}{(r=6),(varphi=pi/2):}

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How do you convert $(0, 6)$ $(0, 6)$ to polar form?

${(r=6),(varphi=pi/2):}$