How do you convert #(0, 6)# to polar form?

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How do you convert #(0, 6)# to polar form?

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Answer 1 · 2017-11-20T19:40:58

See explanation.

Explanation:

graph{(x^2+(y-6)^2-0.1)=0 [-20.27, 20.26, -10.14, 10.13]}

The point #(0,6)# lies on the positive (upper) part of #Y# axis, so the angle between the positive part of the #X# axis and the line containing the point is #pi/2#, the distance between the point #(0,6)# and the origin is #r=6#, so the polar coordinates of #(0,6)# are:

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How do you convert #(0, 6)# to polar form?

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Explanation:

#{(r=6),(varphi=pi/2):}# ##

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