How do you convert #(0, -3)# to polar form? Trigonometry The Polar System Converting Between Systems 1 Answer Shwetank Mauria Mar 14, 2016 #(0,-3)# is #(3,(3pi)/4)# in polar coordinates Explanation: #(r,theta)# in polar coordinates is #(rcostheta,rsintheta)# in rectangular coordinates and #(x,y)# in rectangular coordinates is #(sqrt(x^2+y^2),arctan(y/x))# in polar coordinates. As such, #(0,-3)# in rectangular coordinates will be #(sqrt(0^2+(-3)^2),arctan((-3)/0))# or #(3,(3pi)/4)# in polar coordinates. Answer link Related questions How do you convert rectangular coordinates to polar coordinates? When is it easier to use the polar form of an equation or a rectangular form of an equation? How do you write #r = 4 \cos \theta # into rectangular form? What is the rectangular form of #r = 3 \csc \theta #? What is the polar form of # x^2 + y^2 = 2x#? How do you convert #r \sin^2 \theta =3 \cos \theta# into rectangular form? How do you convert from 300 degrees to radians? How do you convert the polar equation #10 sin(θ)# to the rectangular form? How do you convert the rectangular equation to polar form x=4? How do you find the cartesian graph of #r cos(θ) = 9#? See all questions in Converting Between Systems Impact of this question 2336 views around the world You can reuse this answer Creative Commons License