How do you convert #(0, - 3)# into polar form? Precalculus Polar Coordinates Converting Equations from Polar to Rectangular 1 Answer sankarankalyanam Jul 9, 2018 #color(crimson)((r, theta) = (3, -pi/2)# Explanation: #(x,y) = (0, -3)# #"Conversion from Cartesian to Polar form"# #r = |sqrt(x^2 + y^2)| = |sqrt (0^2 + -3^2)| = 3# #theta = arctan (y/x) = arctan (-3/0) = -90^@ " or " -pi/2# Answer link Related questions What is the polar equation of a horizontal line? What is the polar equation for #x^2+y^2=9#? How do I graph a polar equation? How do I find the polar equation for #y = 5#? What is a polar equation? How do I find the polar equation for #x^2+y^2=7y#? How do I convert the polar equation #r=10# to its Cartesian equivalent? How do I convert the polar equation #r=10 sin theta# to its Cartesian equivalent? How do you convert polar equations to rectangular equations? How do you convert #r=6cosθ# into a cartesian equation? See all questions in Converting Equations from Polar to Rectangular Impact of this question 3019 views around the world You can reuse this answer Creative Commons License