How do you complete the ordered pairs for the equation y = 3x + 9; ( ,0) , (1/3 , ) , (0, ) , (-1/3, )?

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How do you complete the ordered pairs for the equation y = 3x + 9; ( ,0) , (1/3 , ) , (0, ) , (-1/3, )?

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Answer 1 · 2015-07-05T16:02:16

You fill in the known variable in the equation.

Explanation:

(1):

$(x, 0)$ $(x,0)$
$y = 0 \to 0 = 3 x + 9 \to 3 x = - 9 \to x = - 3 \to$ $y=0->0=3x+9->3x=-9->x=-3->$
First pair: $(- 3, 0)$ $(-3,0)$

(2):

$(\frac{1}{3}, y)$ $(1/3,y)$
$x = \frac{1}{3} \to y = 3 \cdot \frac{1}{3} + 9 = 10 \to$ $x=1/3->y=3*1/3+9=10->$
Second pair: $(\frac{1}{3}, 10)$ $(1/3,10)$

I'll leave the other two for you.

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How do you complete the ordered pairs for the equation y = 3x + 9; ( ,0) , (1/3 , ) , (0, ) , (-1/3, )?

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