How do you complete the ordered pair (-6, ?) given 2/3x + y - 1 = 0?

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Answer 1 · 2016-04-28T12:26:06

So $(- 6, ?) \to (- 6, + 5)$ $(-6,?)->(-6,+5)$

Given: $(x, y) \to (- 6, ?)$ $" "(x,y)->(-6,?)$
$\frac{2}{3} x + y - 1 = 0$ $2/3 x+y-1=0$

Thus the unknown value is that of $y$ $y$ and the known value is that of $x$ $x$ .

By substitution for $x = - 6$ $x=-6$

$\frac{2}{3} x + y - 1 = 0 \to \frac{2}{3} (- 6) + y - 1 = 0$ $2/3 x+y-1=0" "->" "2/3(-6)+y-1=0$

$- 4 + y - 1 = 0$ $-4+y-1=0$

$- 5 + y = 0$ $-5+y=0$

Add 5 to both sides

$+ 5 - 5 + y = 0 + 5$ $+5-5+y=0+5$

But $5 - 5 = 0$ $5-5=0$

$y = + 5$ $y=+5$

So $(- 6, ?) \to (- 6, + 5)$ $(-6,?)->(-6,+5)$