How do you complete each ordered pair (_, -1) so that it is a solution to 6x - y = 7?

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Answer 1 · 2016-05-07T21:06:56

$P_{1} \to (x, y) \to (\frac{4}{3}, - 1)$ $P_1->(x,y)->(4/3,-1)$

Given: point 1 $\to P_{1} \to (x, y) \to (?, - 1)$ $->P_1->(x,y)->(?,-1)$

Given: $6 x - y = 7$ $" "6x-y=7$

From $P_{1}; y = - 1$ $P_1; y=-1$

so $6 x - y = 7 \to 6 x - 1 = 7$ $color(brown)(6x-y=7)color(blue)(" "->" "6x-1=7$

Add 1 to both sides

$6 x - 1 + 1 = 7 + 1$ $6x-1+1=7+1$

$6 x + 0 = 8$ $6x+0=8$

Divide both sides by 6

$\frac{6}{6} x = \frac{8}{6}$ $6/6x=8/6$

But 6/6=1#

$x = \frac{8}{6} = \frac{4}{3}$ $x=8/6 = 4/3$

so $P_{1} \to (x, y) \to (\frac{4}{3}, - 1)$ $P_1->(x,y)->(4/3,-1)$