How do you complete 3x-2y=6, and the ordered pairs are (0, .. ) (2,..), and (..,3)?

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How do you complete 3x-2y=6, and the ordered pairs are (0, .. ) (2,..), and (..,3)?

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Answer 1 · 2017-09-11T08:32:19

See explanation.

Explanation:

To calculate the other element in the ordered pair you have to substitute the element given:

First element is $0$ so you put it as $x$ :

$3*color(red)(0)-2y=6$

$-2y=6$

$y=-3$

The pair is $(0,-3)$

First element is $2$ :

$3*color(red)(2)-2y=6$

$-2y=0$

$y=0$

**The pair is $(2,0)$ **

Second element is $3$ , so you put it as $y$ :

$3x-2color(red)(3)=6$

$3x-6=6$

$3x=12$

$x=4$

**The pair is $(4,3)$ **

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How do you complete 3x-2y=6, and the ordered pairs are (0, .. ) (2,..), and (..,3)?

1 Answer

Explanation:

$3*color(red)(0)-2y=6$

$-2y=6$

$y=-3$

$3*color(red)(2)-2y=6$

$-2y=0$

$y=0$

$3x-2color(red)(3)=6$

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Math

Humanities

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How do you complete 3x-2y=6, and the ordered pairs are (0, .. ) (2,..), and (..,3)?

1 Answer

Explanation:

3*color(red)(0)-2y=63*color(red)(0)-2y=6

-2y=6-2y=6

y=-3y=-3

3*color(red)(2)-2y=63*color(red)(2)-2y=6

-2y=0-2y=0

y=0y=0

3*x-2*color(red)(3)=63*x-2*color(red)(3)=6

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Impact of this question

$3*color(red)(0)-2y=6$

$-2y=6$

$y=-3$

$3*color(red)(2)-2y=6$

$-2y=0$

$y=0$

$3x-2color(red)(3)=6$