How do you combine #9/(b+2)+8/(b-7)#?

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Answer 1 · 2015-05-27T18:28:56

To combine #9/(b+2)+8/(b-7)#

you first need to re-write the terms with a common denominator: #(b+2)(b-7)#

#9/(b+2)+8/(b-7)#

#= (9(b-7) + 8(b+2))/((b+2)(b-7))#

#= (9b -63 +8b +16) /((b+2)(b-7))#

#= (17b-47)/(b^2-5b-14)#