How do you combine $1/3 + 7/(3x) - 2/(3x+6)$ ?

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Answer 1 · 2015-05-26T13:24:58

Note $color(red)(3)(x^2+2x) = color(blue)(3x)(x+2)= color(green)((3x+6)(x)$

So $1/color(red)(3) + 7/(color(blue)(3x)) - 2/(color(green)(3x+6))$

$= (3(x^2+2x) +7(x+2)-2(x)) / ( 3x^2+6x)$

$= (3x^2+11x+14)/(3x^2+6x)$

Answer 2 · 2015-05-26T13:31:06

$=1/3(1+7/x-2/(x+2))=1/3(7/x+1-2/(x+2))$

$=1/3(7/x+x/(x+2))$

$=1/3((7(x+2)+x^2)/(x(x+2)))$

$=1/3((7x+14+x^2)/(x(x+2)))$

How do you combine 1/3 + 7/(3x) - 2/(3x+6) 1/3 + 7/(3x) - 2/(3x+6) ?