How do you change #y - -1/4 = -3(x + 1/4)# into slope intercept form?

3 Answers
Shantelle · Jacobi J.
Jul 19, 2018

#y = -3x - 1#

Explanation:

This is slope-intercept form:
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#y - -1/4 = -3(x+1/4)#

First, simplify:
#y + 1/4 = -3x - 3/4#

Now subtract #color(blue)(1/4)# from both sides of the equation:
#y + 1/4 quadcolor(blue)(-quad1/4) = -3x - 3/4 quadcolor(blue)(-quad1/4)#

#y = -3x - 1#

This now matches slope-intercept form, #y = mx + b# where #m = -3# and #b = -1#.

Hope this helps!

Jim G.
Jul 19, 2018

#y=-3x-1#

Explanation:

#"the equation of a line in "color(blue)"slope-intercept form"# is.

#•color(white)(x)y=mx+b#

#"where m is the slope and b the y-intercept"#

#"distribute and rearrange"#

#y+1/4=-3x-3/4#

#"subtract "1/4" from both sides"#

#y=-3x-3/4-1/4#

#y=-3x-1larrcolor(red)"in slope-intercept form"#

Jacobi J.
Jul 19, 2018

#y=-3x-1#

Explanation:

Recall that slope intercept form is given by

#y=mx+b#, with slope #m# and a #y#-intercept of #b#.

We can start by distributing the #-3# on the right to get

#y+1/4=-3x-3/4#

Next, let's subtract #1/4# from both sides to get

#y=-3x-1#

This equation is now in slope-intercept form.

Hope this helps!

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