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How do you change #4^-3 = 1/64# into log form?

1 Answer

Shwetank Mauria

Jul 27, 2016

#log_4(1/64)=-3#

Explanation:

As #a^n=b# in logarithmic form is written as #log_ab=n#

Hence, #4^(-3)=1/64# can be written as #log_4(1/64)=-3#

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