How do you calculate the number of moles of solute in 98.97 mL of 0.1585 M $K_2Cr_2O_7 (aq)$ ?

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Answer 1 · 2017-12-24T09:51:58

Simply take the product... $"volume"xx"concentration"$ to give an answer in $"moles"$ .

By definition, $"Concentration"="Moles of solute"/"Volume of solution"$ .

And thus $n_"moles of solute"="concentration"xx"volume"$

$=0.1585*mol*L^-1xx98.97*mLxx10^-3*L*mL^-1=??*mol$

Note the dimensional consistency of the product. We wanted an answer in moles, and the product gave us one....i.e.

$0.1585*mol*cancel(L^-1)xx98.97*cancel(mL)xx10^-3*cancel(L*mL^-1).$

$=??mol$

How do you calculate the number of moles of solute in 98.97 mL of 0.1585 M K_2Cr_2O_7 (aq)K_2Cr_2O_7 (aq)?