How do you calculate the number of moles of potassium hydroxide that must be dissolved to make the following solution: 500 $cm^3$ of 1 $mol$ $/$ $dm^3$ ?

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Answer 1 · 2016-09-20T17:04:11

We use the relationship, $"Concentration"$ $=$ $"Moles of solute"/"Volume of solution"$ . $0.500*mol$ $KOH$ are required.

We are given that $"Concentration"$ $=$ $1*mol*dm^-3$ , and that the volume of this solution is $500*cm^3$ $=$ $0.500*dm^3$ .

Thus $"moles of solute"$ $=$ $"concentration "xx" volume"$ $=$ $1*mol*cancel(dm^-3)xx0.500*cancel(dm^3)$ $=$ $0.500*mol$ .

What is the mass of the $KOH$ used here?

How do you calculate the number of moles of potassium hydroxide that must be dissolved to make the following solution: 500 cm^3cm^3 of 1 molmol//dm^3dm^3?