How do you calculate the mass of HCI required to prepare 2.5 liters of a 0.08 molar solution of HCI?

1 Answer
Aug 26, 2016

Easy.

Explanation:

2.5 liters of a 0.08 molar solution of HCI gives us moles of HCl in the solution

Molarity*Volume = moles

0.08 (mol)/cancel L * 2.5 cancel L = 0.2 moles HCl

Now you must convert moles to grams

Molar mass of HCl
H = 1.01 (g)/(mol)
Cl = 35 (g)/(mol)

HCl = 1+35=36(g)/(mol)

(0.2 cancel mol)/1 * 36 (g)/(cancel mol) = color (red) (7.2 g) HCl