How do you calculate the grams solute required to make the following solution: 2.5 L of 0.90% of NaCl (m/v)?

1 Answer
Stefan V.
May 13, 2017

Here's how you can do that.

Explanation:

You know that a solution's mass by volume percent concentration, "% m/v", tells you the number of grams of solute present for every "100 mL" of solution.

This implies that a "0.90% m/v" solution will contain "0.90 g" of sodium chloride, the solute, for every "100 mL" of solution.

You can thus say that

2.5 color(red)(cancel(color(black)("L"))) * (10^3color(white)(.)"mL")/(1color(red)(cancel(color(black)("L")))) = 2.5 * 10^3 "mL"

of "0.90% m/v" sodium chloride solution must contain

2.5 * 10^3 color(red)(cancel(color(black)("mL solution"))) * "0.90 g NaCl"/(100color(red)(cancel(color(black)("mL solution"))))= color(darkgreen)(ul(color(black)("23 g NaCl")))

The answer is rounded to two sig figs.

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