How do you calculate the grams solute required to make the following solution: 2.5 L of 0.90% of NaCl (m/v)?

1 Answer
Stefan V.
May 13, 2017

Here's how you can do that.

Explanation:

You know that a solution's mass by volume percent concentration, #"% m/v"#, tells you the number of grams of solute present for every #"100 mL"# of solution.

This implies that a #"0.90% m/v"# solution will contain #"0.90 g"# of sodium chloride, the solute, for every #"100 mL"# of solution.

You can thus say that

#2.5 color(red)(cancel(color(black)("L"))) * (10^3color(white)(.)"mL")/(1color(red)(cancel(color(black)("L")))) = 2.5 * 10^3# #"mL"#

of #"0.90% m/v"# sodium chloride solution must contain

#2.5 * 10^3 color(red)(cancel(color(black)("mL solution"))) * "0.90 g NaCl"/(100color(red)(cancel(color(black)("mL solution"))))= color(darkgreen)(ul(color(black)("23 g NaCl")))#

The answer is rounded to two sig figs.

Related questions
See all questions in Percent Concentration
Impact of this question
15581 views around the world
You can reuse this answer
Creative Commons License