How do you calculate, the derivative of #cos^3x#?

Question

1635 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-11T00:09:06

I would use the Chain Rule to deal separately with the #()^3# and #cos# functions getting:
#y'=3cos^2(x)(-sin(x))=-3sin(x)cos^2(x)#