How do you calculate #log_6 73# with a calculator?

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Answer 1 · 2016-08-31T11:18:27

#x = 2.395#

Log form and index form are interchangeable.

#log_a b = c hArr a^c = b#

Let #log_6 73 = x hArr 6^x = 73#

The variable is in the index, so we need logs.

#log6^x = log73#

#x log6 = log73#

#x = log73/log6#

#x = 2.395#