How do you balance this redox reaction using the oxidation number method? HNO3(aq) + H3AsO3(aq) --> NO(g) + H3AsO4(aq) + H2O(l)
1 Answer
You follow a series of steps in order.
Here are the steps for balancing redox equations.
Your unbalanced equation is
HNO₃ + H₃AsO₃ → NO + H₃AsO₄ + H₂O
Step 1. The oxidation numbers are:
Left hand side: H= +1; N= +5; O = -2; As = +3
Right hand side: N = +2; O = -2; H = +1; As = +5
Step 2. The changes in oxidation number are:
N: +5 → +2; Change = -3
As: +3 → +5; Change = +2
Step 3. You need 3 atoms of As for every 2 atom of N.
This gives you total changes of +6 and -6.
Step 4. Insert coefficients to get these numbers.
2 HNO₃ + 3 H₃AsO₃ → 2 NO + 3 H₃AsO₄ + H₂O
Step 5. Balance O.
2 HNO₃ + 3 H₃AsO₃ → 2 NO + 3 H₃AsO₄ + 1 H₂O
Step 6. Balance H.
Done.
Step 7. Check that all atoms balance.
Left hand side: 11 H; 2 N; 15 O; 3 As
Right hand side: 2 N; 15 O; 11 H; 3 As
The balanced equation is
2HNO₃ + 3H₃AsO₃ → 2NO + 3H₃AsO₄ + H₂O
