How do you balance this equation? $MnO_2 + Al -> Mn + Al_2O_3$

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Answer 1 · 2016-07-07T20:04:48

$3MnO_2+4Al -> 3Mn+2Al_2O_3$

Since we have a multiple of $3$ oxygens on the right hand side we require a multiplier of $3$ on the left hand side.

If we have $3MnO_2$ on the left hand side, then that is a total of $3$ manganeses and $6$ oxygens, requiring $3Mn+2Al_2O_3$ on the right hand side.

Then we need $4$ aluminiums on the left hand side.

Hence the balanced form of the equation is:

$3MnO_2+4Al -> 3Mn+2Al_2O_3$

How do you balance this equation? MnO_2 + Al -> Mn + Al_2O_3MnO_2 + Al -> Mn + Al_2O_3