How do you balance $(NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O$ ?

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How do you balance $(NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O$ ?

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Answer 1 · 2016-06-19T05:45:28

$(NH_4)_2CO_3(aq) + 2NaOH rarr Na_2CO_3(aq) + 2NH_3(aq) + 2H_2O(l)$

Explanation:

The net ionic equation is simply an acid base reaction:

$NH_4^+ + HO^(-) rarr NH_3(aq) + H_2O(l)$

Given that a mineral acid will protonate a carbonate to give water and carbon dioxide gas, what would the reaction if sodium carbonate were treated with 2 equiv hydrochloric acid?

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How do you balance $(NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O$ ?

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How do you balance (NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O(NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O?

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How do you balance $(NH_4)_2CO_3 + NaOH -> Na_2CO_3 + NH_3 + H_2O$ ?