How do you balance #Fe(s) + S(s) -> Fe_2S_3(s)#?

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Answer 1 · 2017-02-22T17:45:03

#2Fe_(s)# + #3S_(s)# ------------> #Fe_2S_3#

Step 1 : First of all write the equation
#Fe_(s)# + #S_(s)# ------------> #Fe_2S_3#

Step 2 : Now balance the number of #Fe# atoms on both reactant and product side

Here reactant side has one #Fe_(S)# atom and product side has #2# atoms of #Fe_(S)#, therefore multiply #Fe_(S)# at reactant side by #2#

Step 3: Balance #S_(s)#

Here reactant side has one #S_(s)# atom and product side has #3# atoms of #S_(s)#, therefore multiply #S_(s)# at reactant side by #3#

Step 4.
Write the final eqaution

#2Fe_(s)# + #3S_(s)# ------------> #Fe_2S_3#