How do you balance $C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)$ ?

Question

How do you balance $C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)$ ?

1 Answer

Impact of this question

1561 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-10T19:42:49

$C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(g)$

Explanation:

You can make the coefficients integral if you like. There is no necessity to do so. There is a necessity to balance the equation. Is it balanced? Does garbage in equal garbage out?

How would energy transfer in this reaction?

Science

Math

Humanities

... and beyond

How do you balance $C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you balance C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you balance $C_4H_10(g) + O_2(g) → CO_2(g) + H_2O(g)$ ?