How do you balance #B_2Br_6 + HNO_3 -> B(NO_3)_3 + HBr#?

1 Answer
anor277
Apr 20, 2017

For a start, your starting material is #BBr_3#.........

Explanation:

And another thing, while #""^(-)B(NO_3)_4# is known, I am pretty sure that #B(NO_3)_3# is UNKNOWN. There was something about its synthesis in the old Russian literature, but given the source, its existence would be fairly suspect........

As an hypothetical reaction, we could write........

#BBr_3+ 3HNO_3 +3NEt_3rarrB(NO_3)_3 + 3Et_3N*HBr#

Note that #BBr_3# reacts very violently with water, and its aqueous chemistry is unknown.

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