How do you add or subtract $(3/x) + (13)/(x – 11)$ ?

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Answer 1 · 2018-05-14T05:21:10

$(3/x) + 13/(x-11)$ = $(16x-33)/(x(x-11)$

By treating this expression same as normal fraction adding and subtracting:

$(3/x) + 13/(x-11)rarr$ common denominator will be $x xx (x-11)$

$(3/x) + 13/(x-11)$ = $(3(x-11) + 13x)/(x(x-11))$

$(3/x) + 13/(x-11)$ = $(3x-33+13x)/(x(x-11))$

$(3/x) + 13/(x-11)$ = $(16x-33)/(x(x-11)$

How do you add or subtract (3/x) + (13)/(x – 11)(3/x) + (13)/(x – 11)?