How do solve $\sqrt{x + 7} + 2 = 4$ $sqrt(x+7)+2=4$ ?

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Answer 1 · 2015-09-14T06:48:27

$x = - 3$ $x=-3$

$\sqrt{x + 7} + 2 = 4$ $sqrt(x+7)+2=4$

Subtract $2$ $2$ from both sides.

$\sqrt{x + 7} = 4 - 2$ $sqrt(x+7)=4-2$

$\sqrt{x + 7} = 2$ $sqrt(x+7)=2$

Square both sides of the equation.

${(\sqrt{x + 7})}^{2} = 2^{2}$ $(sqrt(x+7))^2=2^2$

$x + 7 = 4$ $x+7=4$

Subtract $7$ $7$ from both sides.

$x = 4 - 7$ $x=4-7$

$x = - 3$ $x=-3$

How do solve sqrt(x+7)+2=4√x+7+2=4sqrt(x+7)+2=4?