How do solve $-5/(x+3)^2>0$ graphically?

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Answer 1 · 2016-12-07T10:45:56

There is no solution.

Is the question correct? Have you got the inequality round the correct way?

Set $" "y=-5/((x+3)^2) >0$

The question requires that $y>0$

Observation that the graph implies that as $x$ tends to $+-oo$ $y$ tends to 0

However, the question states that we require $y>0$

Clearly there is no $y$ greater than 0 so $color(red)("there is no solution")$

Consider the graph:

Tony N

How do solve -5/(x+3)^2>0-5/(x+3)^2>0 graphically?