How do I solve tan9x-tan2x=tan9xtan6xtan3x+tan6xtan4xtan2xtan9x−tan2x=tan9xtan6xtan3x+tan6xtan4xtan2x?
1 Answer
Jul 16, 2017
Explanation:
Consider
Then,
(tana+tanb)/(1-tanatanb)=tanc
tana+tanb=tanc(1-tanatanb)
tana+tanb=tanc-tanctanatanb
tanctanatanb=tanc-tana-tanb
If we consider the integer triplet
If we apply the same consideration to
Substituting (2) and (3) into (1) yields