How do I resolve indeterminate limits?

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Answer 1 · 2016-12-16T15:14:13

This is not an indeterminate limit. It can be found by substitution.

#lim_(xrarr3)(x^2+2x-1) = 9+6-1 = 14#

so,

#lim_(xrarr3)xsqrt(x^2+2x-1) = 3sqrt(9+6-1) = 3sqrt14#