How do find the vertex and axis of symmetry, and intercepts for a quadratic equation #y=x^2-7x-28#?
1 Answer
Jun 9, 2015
Find vertex of y = x^2 - 7x - 28
Explanation:
x of vertex:
y of vertex:
x of axis of symmetry = x of vertex =
To find y-intercept, make x = 0 -> y = -28
To find x-intercepts, make y = 0
x-intercepts:
