How do find the derivative of #y= (1- sec x)/ tan x#?

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Answer 1 · 2018-07-30T18:53:04

#(dy)/(dx)=cscx(cotx-cscx)#

Here ,

#y=(1-secx)/tanx#

#=>y=1/tanx-secx/tanx#

#=>y=cotx-(1/cosx)/(sinx/cosx)#

#=>y=cotx-cscx#

#(dy)/(dx)=-csc^2x-(-cscxcotx)#

#(dy)/(dx)=-csc^2x+cscxcotx#

#:.(dy)/(dx)=cscx(cotx-cscx)#