How can this be solved?

Question

How can this be solved?

$cos 4 x (cos x - 1) = 0$ $cos4x(cosx-1) = 0$

Can you also let me know what the +1 equals to in a situation?

For example, "cosx + 1", along with other functions that have a +1

1 Answer

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Answer 1 · 2018-03-24T22:38:13

To answer your other question:
So:
$x = 0 + 2 π n$ $x=0+2pin$
$x = \frac{π}{8} + \frac{π}{2} n$ $x= pi/8+pi/2n$
$x = \frac{3 π}{8} + \frac{π}{2} n$ $x= (3pi)/8+pi/2n$

Explanation:

$cos 4 x (cos x - 1) = 0$ $cos4x(cosx-1)=0$

$cos x = 1$ $cosx=1$
$cos 4 x = 0$ $cos4x=0$

$x = 0 + 2 π n$ $x=0+2pin$
$4 x = \frac{π}{2} + 2 π n$ $4x= pi/2+2pin$
$4 x = \frac{3 π}{2} + 2 π n$ $4x= (3pi)/2+2pin$

So:
$x = 0 + 2 π n$ $x=0+2pin$
$x = \frac{π}{8} + \frac{π}{2} n$ $x= pi/8+pi/2n$
$x = \frac{3 π}{8} + \frac{π}{2} n$ $x= (3pi)/8+pi/2n$

Here's a graph:
graph{cos(4x)(cosx-1) [-10, 10, -5, 5]}

To answer your other question:

"For example, "cosx + 1", along with other functions that have a +1":

The $+ 1$ $+1$ symbolizes a vertical shift, the function $cos x$ $cosx$ has been shifted up 1 unit

For example:

graph{cosx [-10, 10, -5, 5]}
Graph of Cosx
graph{cosx+1 [-10, 10, -5, 5]}
Graph of Cosx+1

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How can this be solved?

$cos 4 x (cos x - 1) = 0$ $cos4x(cosx-1) = 0$

Can you also let me know what the +1 equals to in a situation?

For example, "cosx + 1", along with other functions that have a +1

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How can this be solved?

cos4x(cosx-1) = 0cos4x(cosx−1)=0cos4x(cosx-1) = 0 Can you also let me know what the +1 equals to in a situation? For example, "cosx + 1", along with other functions that have a +1

1 Answer

Explanation:

Related questions

Impact of this question

$cos 4 x (cos x - 1) = 0$ $cos4x(cosx-1) = 0$

Can you also let me know what the +1 equals to in a situation?

For example, "cosx + 1", along with other functions that have a +1