How can this be solved?

Question

#cos4x(cosx-1) = 0#

Can you also let me know what the +1 equals to in a situation?

For example, "cosx + 1", along with other functions that have a +1

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Answer 1 · 2018-03-24T22:38:13

To answer your other question:
So:
#x=0+2pin#
#x= pi/8+pi/2n#
#x= (3pi)/8+pi/2n#

#cos4x(cosx-1)=0#

#cosx=1#
#cos4x=0#

#x=0+2pin#
#4x= pi/2+2pin#
#4x= (3pi)/2+2pin#

So:
#x=0+2pin#
#x= pi/8+pi/2n#
#x= (3pi)/8+pi/2n#

Here's a graph:
graph{cos(4x)(cosx-1) [-10, 10, -5, 5]}

To answer your other question:

"For example, "cosx + 1", along with other functions that have a +1":

The #+1# symbolizes a vertical shift, the function #cosx# has been shifted up 1 unit

For example:

graph{cosx [-10, 10, -5, 5]}
Graph of Cosx
graph{cosx+1 [-10, 10, -5, 5]}
Graph of Cosx+1