How can I solve #y=a(x-1)^2+k# when they only give me two points which are : (2,6) and (3,12)?

1 Answer
Blackad
Jun 20, 2018

You just need to plug the points and then solve that.

Explanation:

Because #(2,6)# is in the function, we can plug #6# as #y# and #2# as x.
From that we get #6=a(2-1)^2+k#
#6=a+k#
Same for the next point: #12=a(3-1)^2+k#
#12=2^2a+k#
#12=4a+k#

Now we have this system of equations to solve:
#a+k=6#
#4a+k=12#
Solving it leads to the conclusion that #a=2,k=4#.

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