How can I find the percent compositions of N2S2?

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Answer 1 · 2014-05-28T23:45:07

To find the percent composition of N₂S₂, you divide the total mass of each atom by the molecular mass and multiply by 100 %.

% by mass = $\frac{mass of component}{total mass}$ $"mass of component"/"total mass"$ × 100 %

Mass of 2 N atoms = 2 N atoms × $\frac{14.01 u}{1 N atom}$ $(14.01"u")/(1"N atom")$ = 28.02 u.

Mass of 2 S atoms = 2 S atoms × $\frac{32.06 u}{1 S atom}$ $(32.06"u")/(1"S atom")$ = 64.12 u

Mass of 1 N₂S₂ molecule = (28.02 + 64.12) u = 92.14 u

% of N = $\frac{mass of N}{total mass}$ $"mass of N"/"total mass"$ × 100 % = $\frac{28.02 u}{92.14 u}$ $(28.02"u")/(92.14"u")$ × 100 % =30.41 %

% of S = $\frac{mass of S}{total mass}$ $"mass of S"/"total mass"$ × 100 % = $\frac{64.12 u}{92.14 u}$ $(64.12"u")/(92.14"u")$ × 100 % =69.59 %