How can I check if a given line lies in a given plane or not?

For example, how do I check if the line (1,2,3) + t(1,0,1) lies in the plane x+2y+2z+1=0

1 Answer
Apr 16, 2017

See below.

Explanation:

A plane Pi can be represented as

<< p - p_0, vec n >> = 0

here << cdot, cdot >> represents the scalar product of two vectors.

in our case we have

p = (x,y,z)
vec n = (1,2,2) and
p_0 = (-1,0,0)

A line L can be represented as

L->p = p_1+t vec v

in our case we have

p = (x,y,z)
p_1=(1,2,3) and
vec v = (1,0,1)

Now, if L sub Pi then

<< p_1+t vec v - p_0, vec n >> = 0, forall t in RR or

<< p_1-p_0, vec n >> + t << vec v, vec n >> = 0

This occurs when << vec v, vec n >> = 0 being orthogonals, and also << p_1-p_0, vec n >> = 0 being orthogonals also.

In the present case we have

<< vec v, vec n >> = 1 xx 1+ 2xx0+2xx1=3 ne 0 and

<< p_1-p_0, vec n >> = 2xx1+ 2xx2+ 3xx2=12 ne 0

so concluding, L does not lies into Pi