How to find the initial pressure?
Here's my work :
#T_1=74+273.15 = 347.15 k #
#T_2 = 120+273.15 = 393.15 k #
#P_2=1.79 atm #
#P_1 T_1 = P_2 T_2#
#P_1 = ( 393.15*1.79)/347.15 = 2.027 atm#
Could somebody solve this problem ?
Here's my work :
Could somebody solve this problem ?
1 Answer
The initial pressure was 1.58 atm.
Explanation:
Since the volume is constant but the pressure and temperature are changing, this is an example of Gay-Lussac's Law:
#color(blue)(bar(ul(|color(white)(a/a)p_1/T_1=p_2/T_2color(white)(a/a)|)))" "#
We can rearrange the above formula to get
#p_1=p_2 × T_1/T_2#
Your data are:
The initial pressure was 1.58 atm.
(You used the wrong formula for Gay-Lussac's Law.)