Helene is asked to solve the equation $3sin^2theta-2sintheta=0$ for $0<=theta<=pi$ , she find that $theta=pi$ . How could she check whether this is a correct root for the equation?

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Helene is asked to solve the equation $3sin^2theta-2sintheta=0$ for $0<=theta<=pi$ , she find that $theta=pi$ . How could she check whether this is a correct root for the equation?

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Answer 1 · 2016-11-24T20:06:14

see explanation.

Explanation:

Substitute the solution, that is $theta=pi$ into the original equation and if it makes the equation true then it is a correct root of the equation.

$" Check that" 3sin^2theta-2sintheta=0" is true"$

$rArr3sin^2(pi)-2sin(pi)$

$"Now" sin(pi)=0$

$rArr3(0)^2-2(0)=0larr" satisfies equation"$

$"thus " theta=pi" is a correct root"$

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Helene is asked to solve the equation $3sin^2theta-2sintheta=0$ for $0<=theta<=pi$ , she find that $theta=pi$ . How could she check whether this is a correct root for the equation?

1 Answer

Explanation:

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Helene is asked to solve the equation 3sin^2theta-2sintheta=03sin^2theta-2sintheta=0 for 0<=theta<=pi0<=theta<=pi, she find that theta=pitheta=pi. How could she check whether this is a correct root for the equation?

1 Answer

Explanation:

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Helene is asked to solve the equation $3sin^2theta-2sintheta=0$ for $0<=theta<=pi$ , she find that $theta=pi$ . How could she check whether this is a correct root for the equation?