# Given #y+3=-2/3(x-3)# what is the slope and point on the graph?

##### 1 Answer

Nov 20, 2016

#### Explanation:

The equation of a line in

#color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#

where m represents the slope and b, the y-intercept.Rearrange the given equation into this form.

distribute bracket on right side.

#rArry+3=-2/3x+2# subtract 3 from both sides.

#rArry=-2/3x-1#

#rArrm=-2/3" and " b=-1# y-intercept = - 1 which is the coordinate point (0 ,-1)

To obtain any coordinate point on the line, select values for x and substitute them into the equation for corresponding value of y.

#x=3rArry=(-2/3xx3)-1=-2-1=-3#

#rArr(3,-3)" is also a point on the line"#

graph{-2/3x-1 [-10, 10, -5, 5]}