Given #((x + 3)(x - 4)) / ((x + 3)(x + 1)## how do you find the limit as x approaches -3?
1 Answer
Jun 6, 2016
Explanation:
as
#xto-3# , the factor (x+3) on the numerator and denominator will be zero and we will obtain.
#0/0" which is undefined."# By cancelling we can eliminate this situation.
#((cancel(x+3))(x-4))/(cancel((x+3))(x+1))=(x-4)/(x+1)# and now we have a simplified function.
#rArrlim_(xto-3) (x-4)/(x+1)=(-3-4)/(-3+1)=7/2#
