Given $W=3^(x+y)$ , how do you solve for x?

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Answer 1 · 2016-11-08T01:01:27

$lnW = ln(3^(x + y))$

$lnW = (x + y)ln3$

$lnW = xln3 + yln3$

$lnW - yln3 = xln3$

$(lnW - yln3)/ln3 = x$

$(ln(W/3))/ln3 = x$

Hopefully this helps!

Answer 2 · 2016-11-08T01:29:14

$x=log_3 W-y=log W/log 3 - y$ .

Inversely,

$x+y=log_3W$

$x=log_3 W-y$ .

Given W=3^(x+y)W=3^(x+y), how do you solve for x?