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Given three points (-2,2), (-1,-1),(2,6) how do you write a quadratic function in standard form with the points?

1 Answer

Nov 3, 2017

#y=4/3*x^2+x-4/3=(4x^2+3x-4)/3#

Explanation:

Searched quadratic function is #y=ax^2+bx+c#

After imposing conditions,

#4a-2b+c=2#, #a-b+c=-1# and #4a+2b+c=6#

After solving this equation system,

#b=1#, #a=4/3# and #c=-4/3#

Thus, #y=4/3*x^2+x-4/3=(4x^2+3x-4)/3#

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